-227-9x=3+7x-8x^2

Solution for -227-9x=3+7x-8x^2 equation:

-227-9x=3+7x-8x^2

We move all terms to the left:

-227-9x-(3+7x-8x^2)=0

We get rid of parentheses

8x^2-7x-9x-3-227=0

We add all the numbers together, and all the variables

8x^2-16x-230=0

a = 8; b = -16; c = -230;
Δ = b2-4ac
Δ = -162-4·8·(-230)
Δ = 7616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7616}=\sqrt{64*119}=\sqrt{64}*\sqrt{119}=8\sqrt{119}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{119}}{2*8}=\frac{16-8\sqrt{119}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{119}}{2*8}=\frac{16+8\sqrt{119}}{16}
$